QJEEM24Ch3cd2: JEE Main 2024 Chemistry - Class 11 JEEM24Ch3cd2 Solution: The number of moles of methane required to produce 11 g CO2(g)…

To find the number of moles of methane ( $CH_4$ ) required to produce 11g of $CO_2$ upon complete combustion, we first need the balanced chemical equation for the combustion of methane:

CH4+2O2→CO2+2H2O

From the balanced equation, we see that 1 mole of $CH_4$ produces 1 mole of $CO_2$ . Therefore, the moles of $CH_4$ needed to produce a certain amount of $CO_2$ will be equal to the moles of $CO_2$ produced.

To find the moles of $CO_2$ produced from 11g of $CO_2$ , we use the formula:

Moles=MassMolar mass

The molar mass of $CO_2$ is $44 \mathrm{~g/mol}$ (12 from carbon and 16 $\times$ 2 from oxygen). Then, the moles of $CO_2$ produced from 11g of $CO_2$ can be calculated as:

Moles of CO2=11 g44g/mol=0.25 mol

Since the stoichiometry of the reaction between methane and oxygen is 1:1 for $CH_4$ and $CO_2$ , the moles of $CH_4$ required to produce 11g of $CO_2$ is also 0.25 moles.

Therefore, the correct answer is Option B: 0.25.