Verified Solution • 2025–26 Session moderate

QJEEM24Ch359b: JEE Main 2024 Chemistry - Class 11 JEEM24Ch359b Solution: Consider the following reaction at 298   K ⋅ 3 2 O 2 ( g ) …

Consider the following reaction at 298 K⋅32O2(g)⇌O3(g)⋅KP=2.47×10−29. ΔrG⊖ for the reaction is _________ kJ. (Given R=8.314 JK−1 mol−1)

Step-by-Step Verified Solution

32O2( g)⇌O3( g)⋅KP=2.47×10−29.ΔrGΘ=−RTln⁡KP=−8.314×10−3×298×ln⁡(2.47×10−29)=−8.314×10−3×298×(−65.87)=163.19 kJ

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