Verified Solution • 2025–26 Session moderate

QJEEM24Ch30db: JEE Main 2024 Chemistry - Class 12 JEEM24Ch30db Solution: The mass of zinc produced by the electrolysis of zine sulphate…

The mass of zinc produced by the electrolysis of zine sulphate solution with a steady current of 0.015 A0.015 \mathrm{~A} for 15 minutes is _________ ×10−4 g\times 10^{-4} \mathrm{~g} .

(Atomic mass of zinc =65.4 amu=65.4 \mathrm{~amu} )

Step-by-Step Verified Solution

amp;Zn+2+2e−⟶Znamp;W=Z×i×tamp;=65.42×96500×0.015×15×60amp;=45.75×10−4gm\begin{aligned} & \mathrm{Zn}^{+2}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Zn} \\ & \mathrm{W}=\mathrm{Z} \times \mathrm{i} \times \mathrm{t} \\ & =\frac{65.4}{2 \times 96500} \times 0.015 \times 15 \times 60 \\ & =45.75 \times 10^{-4} \mathrm{gm}\end{aligned}

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