Verified Solution • 2025–26 Session moderate

QJEEM24Ch302a: JEE Main 2024 Chemistry - Class 12 JEEM24Ch302a Solution: when treated with gives green colour solution of . The two…

0.05M CuSO40.05 \mathrm{M} \mathrm{~CuSO}_4 when treated with 0.01M K2Cr2O70.01 \mathrm{M} \mathrm{~K}_2 \mathrm{Cr}_2 \mathrm{O}_7 gives green colour solution of Cu2Cr2O7\mathrm{Cu}_2 \mathrm{Cr}_2 \mathrm{O}_7 . The two solutions are separated as shown below : [SPM : Semi Permeable Membrane]

JEE Main 2024 (Online) 9th April Morning Shift Chemistry - Solutions Question 16 English

Due to osmosis :

Multiple Choice Options

  • A Molarity of K2Cr2O7\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 solution is lowered.
  • B Green colour formation observed on side Y.
  • C Molarity of CuSO4\mathrm{CuSO}_4 solution is lowered.
  • D Green colour formation observed on side X.

Step-by-Step Verified Solution

Osmosis leads to the net movement of water molecule from low osmotic pressure to high osmotic pressure. Since the iM value of 0.05 M CuSO40.05 \mathrm{~M} \mathrm{~CuSO}_4 solution is higher hence it has higher osmotic pressure so the water moves towards CuSO4\mathrm{CuSO}_4 solution leads to drop of its molarity. The solute molecules do not cross S.P.M. via osmosis.

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