QJEEM24Ch24d7: JEE Main 2024 Chemistry - Class 11 JEEM24Ch24d7 Solution: Match List I with List II .tg…

To match each element with its correct electronic configuration, let's consider the electronic configurations of each element based on their positions in the periodic table:

• Nitrogen (N): It is in the 2nd period and belongs to the p-block, specifically group 15. The electronic configuration of nitrogen is $1\text{s}^2 2\text{s}^2 2\text{p}^3$ . Looking at the options in List II, this matches with the electronic configuration labeled 'III' ( $[\mathrm{He}] 2 \mathrm{s}^2 2 \mathrm{p}^3$ ), which reflects the electronic configuration of nitrogen starting after the helium core.


• Sulfur (S): Sulfur is in the 3rd period, also in the p-block, specifically group 16. Its electronic configuration is $1\text{s}^2 2\text{s}^2 2\text{p}^6 3\text{s}^2 3\text{p}^4$ . In the given list, this corresponds to 'II' ( $[\mathrm{Ne}] 3 \mathrm{s}^2 3 \mathrm{p}^4$ ), which captures the configuration of sulfur starting after the neon core.


• Bromine (Br): Bromine is located in the 4th period and in the p-block, belonging to group 17. Its electronic configuration is $1\text{s}^2 2\text{s}^2 2\text{p}^6 3\text{s}^2 3\text{p}^6 3\text{d}^{10} 4\text{s}^2 4\text{p}^5$ , which is correctly represented by 'I' ( $[\mathrm{Ar}] 3 \mathrm{d}^{10} 4 \mathrm{s}^2 4 \mathrm{p}^5$ ), showing the configuration after the argon core.


• Krypton (Kr): Krypton falls in the 4th period and is a noble gas situated in the p-block at group 18. Its electronic configuration is $1\text{s}^2 2\text{s}^2 2\text{p}^6 3\text{s}^2 3\text{p}^6 3\text{d}^{10} 4\text{s}^2 4\text{p}^6$ , which aligns with 'IV' ( $[\mathrm{Ar}] 3 \mathrm{d}^{10} 4 \mathrm{s}^2 4 \mathrm{p}^6$ ), clearly depicting krypton's electronic configuration post-argon.

Therefore, the correct match is:

1. A-III (Nitrogen matches with $[\mathrm{He}] 2 \mathrm{s}^2 2 \mathrm{p}^3$ )
2. B-II (Sulfur matches with $[\mathrm{Ne}] 3 \mathrm{s}^2 3 \mathrm{p}^4$ )
3. C-I (Bromine matches with $[\mathrm{Ar}] 3 \mathrm{d}^{10} 4 \mathrm{s}^2 4 \mathrm{p}^5$ )
4. D-IV (Krypton matches with $[\mathrm{Ar}] 3 \mathrm{d}^{10} 4 \mathrm{s}^2 4 \mathrm{p}^6$ )

Thus, the correct answer is Option C: A-III, B-II, C-I, D-IV.