QJEEM24Ch0463: JEE Main 2024 Chemistry - Class 11 JEEM24Ch0463 Solution: The correct set of four quantum numbers for the valence…

The correct set of four quantum numbers for the valence electron of a rubidium atom ( $Z = 37$ ) is:

Principal quantum number ( $n$ ): This indicates the main energy level or shell of the electron. For rubidium, the valence electron is in the 5th energy level, so $n = 5$ .

Azimuthal quantum number ( $l$ ): This defines the subshell or orbital type. The possible values for $l$ range from 0 to $n-1$ . For rubidium, the valence electron is in the $5s$ orbital, so $l = 0$ .

Magnetic quantum number ( $m_l$ ): This indicates the orientation of the orbital in space. For $l = 0$ , the only possible value is $m_l = 0$ .

Spin quantum number ( $m_s$ ): This represents the spin of the electron, which can be either $+\frac{1}{2}$ or $-\frac{1}{2}$ . Generally, when an electron is added to an unoccupied orbital, it starts with a spin of $+\frac{1}{2}$ .

Therefore, the correct set of quantum numbers for the valence electron of rubidium is:

Option B: $5,0,0,+\frac{1}{2}$