Verified Solution • 2025–26 Session moderate

QJEEM24Ch045a: JEE Main 2024 Chemistry - Class 12 JEEM24Ch045a Solution: of pure aniline is treated with bromine water at room…

9.3 g9.3 \mathrm{~g} of pure aniline is treated with bromine water at room temperature to give a white precipitate of the product ' P\mathrm{P} '. The mass of product ' P\mathrm{P} ' obtained is 26.4 g26.4 \mathrm{~g} . The percentage yield is ________ %.

Step-by-Step Verified Solution

JEE Main 2024 (Online) 5th April Morning Shift Chemistry - Compounds Containing Nitrogen Question 20 English Explanation

moles of aniline taken =9.393=0.1=\frac{9.3}{93}=0.1

% yield =26.40.1×330×100=80%\% \text { yield }=\frac{26.4}{0.1 \times 330} \times 100=80 \%

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring