Verified Solution • 2025–26 Session moderate

QJEEM23Phf1ed: JEE Main 2023 Physics - Class 11 JEEM23Phf1ed Solution: A travelling wave is described by the equation m The velocity…

A travelling wave is described by the equation

y(x,t)=[0.05sin⁡(8x−4t)]y(x,t) = [0.05\sin (8x - 4t)] m

The velocity of the wave is : [all the quantities are in SI unit]

Multiple Choice Options

  • A 4 ms−1\mathrm{4~ms^{-1}}
  • B 2 ms−1\mathrm{2~ms^{-1}}
  • C 8 ms−1\mathrm{8~ms^{-1}}
  • D 0.5 ms−1\mathrm{0.5~ms^{-1}}

Step-by-Step Verified Solution

∵y(x,t)=[0.05sin⁡(8x−4t)]m\because y(x, t)=[0.05 \sin (8 x-4 t)] \mathrm{m}

 Speed of wave amp;=∣ Coefficient of t Coefficient of x∣amp;=48=0.5 ms−1\begin{aligned}\text { Speed of wave } & =\left|\frac{\text { Coefficient of } t}{\text { Coefficient of } x}\right| \\\\& =\frac{4}{8}=0.5 \mathrm{~ms}^{-1}\end{aligned}

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