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QJEEM23Phf1e3: JEE Main 2023 Physics - Class 12 JEEM23Phf1e3 Solution: As shown in the figure, a long straight conductor with…

As shown in the figure, a long straight conductor with semicircular arc of radius $\frac{π}{10}$ m is carrying current $I = 3 A$ . The magnitude of the magnetic field, at the center O of the arc is :

(The permeability of the vacuum $= 4 π \times 10^{- 7} {NA}^{- 2}$ )

JEE Main 2023 (Online) 1st February Evening Shift Physics - Magnetic Effect of Current Question 73 English

Multiple Choice Options

A 4μT
B 3μT
C 6μT
D 1μT

Step-by-Step Verified Solution

JEE Main 2023 (Online) 1st February Evening Shift Physics - Magnetic Effect of Current Question 73 English Explanation

Magnetic field due to two straight wire will be zero as point O is on the axis of the wire. Magnetic field at

B

will be only due to the semicircular arc.

\begin{aligned} So, B & = (\frac{μ_{0} i}{4 r}) = \frac{(4 π \times 10^{- 7}) \times 3}{4 \times (\frac{π}{10})} \\ = 3 \times 10^{- 6} T \\ = 3 μ T \end{aligned}

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