QJEEM23Pheb0c: JEE Main 2023 Physics - Class 12 JEEM23Pheb0c Solution: An LCR series circuit of capacitance 62.5 nF and resistance of…

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QJEEM23Pheb0c: JEE Main 2023 Physics - Class 12 JEEM23Pheb0c Solution: An LCR series circuit of capacitance 62.5 nF and resistance of…

An LCR series circuit of capacitance 62.5 nF and resistance of 50 $Ω$ , is connected to an A.C. source of frequency 2.0 kHz. For maximum value of amplitude of current in circuit, the value of inductance is __________ mH.

(Take $π^{2} = 10$ )

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Accepted Answer

\because

For maximum amplitude of current, circuit should be at resonance.

\begin{aligned} ∴ X_{L} = X_{C} \\ ω L = \frac{1}{ω C} \\ L = \frac{1}{ω^{2} C} \\ = \frac{1}{{(2 π \times 2 \times 10^{3})}^{2} \times 62.5 \times 10^{- 9}} \\ = 100 mH \end{aligned}

QJEEM23Pheb0c: JEE Main 2023 Physics - Class 12 JEEM23Pheb0c Solution: An LCR series circuit of capacitance 62.5 nF and resistance of…

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