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QJEEM23Phea63: JEE Main 2023 Physics - Class 11 JEEM23Phea63 Solution: A solid sphere of mass 2 kg is making pure rolling on a…

A solid sphere of mass 2 kg is making pure rolling on a horizontal surface with kinetic energy 2240 J. The velocity of centre of mass of the sphere will be _______ ms −1^{-1} .

Step-by-Step Verified Solution

12mvcm2+12×25mR2×vcm2R2=2240 J\frac{1}{2} m v_{\mathrm{cm}}^{2}+\frac{1}{2} \times \frac{2}{5} m R^{2} \times \frac{v_{\mathrm{cm}}^{2}}{R^{2}}=2240 \mathrm{~J}

amp;710mvcm2=2240amp;vcm=2240×107×2=40 m/sec\begin{aligned}& \frac{7}{10} m v_{\mathrm{cm}}^{2}=2240 \\\\& v_{\mathrm{cm}}=\sqrt{\frac{2240 \times 10}{7 \times 2}}=40 \mathrm{~m} / \mathrm{sec}\end{aligned}

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