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QJEEM23Phdd01: JEE Main 2023 Physics - Class 12 JEEM23Phdd01 Solution: A zener diode of power rating 1.6 W is to be used as voltage…

A zener diode of power rating 1.6 W is to be used as voltage regulator. If the zener diode has a breakdown of 8V and it has to regulate voltage fluctuating between 3 V and 10 V. The value of resistance Rs for safe operation of diode will be

JEE Main 2023 (Online) 10th April Morning Shift Physics - Semiconductor Question 37 English

Multiple Choice Options

  • A 13 Ω\Omega
  • B 13.3 Ω\Omega
  • C 10 Ω\Omega
  • D 12 Ω\Omega

Step-by-Step Verified Solution

JEE Main 2023 (Online) 10th April Morning Shift Physics - Semiconductor Question 37 English Explanation

Power rating of zener =1.6 W=1.6 \mathrm{~W}

Maximum voltage across zener =8 V=8 \mathrm{~V}

Using P=VIP=V I , for zenner diode,

I=PV=1.68=0.2 AI=\frac{P}{V}=\frac{1.6}{8}=0.2 \mathrm{~A}

Hence, for safe operation, 2 V2 \mathrm{~V} (excess voltage of 10 V10 \mathrm{~V} from 8 V8 \mathrm{~V} ), potential drop must occur in series resistor RSR_S .

For RS,V=2 VR_S, V=2 \mathrm{~V} and I=0.2 AI=0.2 \mathrm{~A}

Using V=IRV=I R ,

R=20.2=10ΩR=\frac{2}{0.2}=10 \Omega

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