Verified Solution • 2025–26 Session moderate

QJEEM23Phd94c: JEE Main 2023 Physics - Class 12 JEEM23Phd94c Solution: A bar magnet with a magnetic moment is placed in parallel…

A bar magnet with a magnetic moment 5.0Am25.0 \mathrm{Am}^{2} is placed in parallel position relative to a magnetic field of 0.4 T0.4 \mathrm{~T} . The amount of required work done in turning the magnet from parallel to antiparallel position relative to the field direction is _____________.

Multiple Choice Options

  • A zero
  • B 1 J
  • C 2 J
  • D 4 J

Step-by-Step Verified Solution

W=−MB(cos⁡θ2−cos⁡θ1)W=-M B\left(\cos \theta_{2}-\cos \theta_{1}\right)

=amp;−0.4×5[cos⁡180∘−cos⁡0]=amp;4 J\begin{aligned}= & -0.4 \times 5\left[\cos 180^{\circ}-\cos 0\right] \\\\= & 4 \mathrm{~J}\end{aligned}

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