Verified Solution • 2025–26 Session moderate

QJEEM23Phd724: JEE Main 2023 Physics - Class 12 JEEM23Phd724 Solution: The electric potential at the centre of two concentric half…

The electric potential at the centre of two concentric half rings of radii R 1_1 and R 2_2 , having same linear charge density λ\lambda is :

JEE Main 2023 (Online) 24th January Evening Shift Physics - Electrostatics Question 69 English

Multiple Choice Options

  • A λ2∈0\frac{\lambda}{2\in_0}
  • B λ∈0\frac{\lambda}{\in_0}
  • C 2λ∈0\frac{2\lambda}{\in_0}
  • D λ4∈0\frac{\lambda}{4\in_0}

Step-by-Step Verified Solution

V1=14πε0×λ(πR1)R1V_{1}=\frac{1}{4 \pi \varepsilon_{0}} \times \frac{\lambda\left(\pi R_{1}\right)}{R_{1}}

V2=amp;14πε0×λ(πR2)R2Vnet amp;=V1+V2amp;=2×14πε0πλamp;=λ2ε0\begin{aligned}V_{2}= & \frac{1}{4 \pi \varepsilon_{0}} \times \frac{\lambda\left(\pi R_{2}\right)}{R_{2}} \\\\V_{\text {net }} & =V_{1}+V_{2} \\\\& =2 \times \frac{1}{4 \pi \varepsilon_{0}} \pi \lambda \\\\& =\frac{\lambda}{2 \varepsilon_{0}}\end{aligned}

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring