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QJEEM23Phd6b8: JEE Main 2023 Physics - Class 11 JEEM23Phd6b8 Solution: A disc is rolling without slipping on a surface. The radius of…

A disc is rolling without slipping on a surface. The radius of the disc is RR . At t=0t=0 , the top most point on the disc is A\mathrm{A} as shown in figure. When the disc completes half of its rotation, the displacement of point A from its initial position is

JEE Main 2023 (Online) 13th April Morning Shift Physics - Rotational Motion Question 43 English

Multiple Choice Options

  • A R(π2+1)R\sqrt {({\pi ^2} + 1)}
  • B 2R2R
  • C R(π2+4)R\sqrt {({\pi ^2} + 4)}
  • D 2R(1+4π2)2R\sqrt {(1 + 4{\pi ^2})}

Step-by-Step Verified Solution

JEE Main 2023 (Online) 13th April Morning Shift Physics - Rotational Motion Question 43 English Explanation
amp; Displacement of CM=RωT2=πramp;⇒ Displacement of A=(2R)2+(πR)2amp;=Rπ2+4\begin{aligned}& \text { Displacement of } C M=R \omega \frac{T}{2}=\pi r \\\\& \Rightarrow \text { Displacement of } A =\sqrt{(2 R)^2+(\pi R)^2} \\\\& =R \sqrt{\pi^2+4}\end{aligned}

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