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QJEEM23Phd369: JEE Main 2023 Physics - Class 11 JEEM23Phd369 Solution: A metal block of base area 0.20 m is placed on a table, as…

A metal block of base area 0.20 m 2^2 is placed on a table, as shown in figure. A liquid film of thickness 0.25 mm is inserted between the block and the table. The block is pushed by a horizontal force of 0.1 N and moves with a constant speed. IF the viscosity of the liquid is 5.0×10−3 Pl5.0\times10^{-3}~\mathrm{Pl} , the speed of block is ____________ ×10−3\times10^{-3} m/s.

JEE Main 2023 (Online) 29th January Evening Shift Physics - Properties of Matter Question 95 English

Step-by-Step Verified Solution

As the block moves with constant speed, the horizontal force is balanced by viscous force thus

F=ηAΔvΔzF = \eta A{{\Delta v} \over {\Delta z}}

0.1=5×10−3×0.2×v.25×10−30.1 = 5 \times {10^{ - 3}} \times 0.2 \times {v \over {.25 \times {{10}^{ - 3}}}}

⇒v=25×10−3\Rightarrow v = 25 \times {10^{ - 3}} m/s

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