QJEEM23Phd2fe: JEE Main 2023 Physics - Class 12 JEEM23Phd2fe Solution: The modulation index for an A.M. wave having maximum and…

The modulation index (m) of an amplitude-modulated wave is defined as the ratio of the amplitude of the modulating signal to the amplitude of the carrier wave. It is a measure of the degree of modulation of the carrier wave and is given by the following equation:

$m = \frac{V_{max} - V_{min}}{V_{max} + V_{min}}$

Where $V_{max}$ is the maximum peak-to-peak voltage and $V_{min}$ is the minimum peak-to-peak voltage.

Plugging in the values from the question, we have:

$m = \frac{14 \text{ mV} - 6 \text{ mV}}{14 \text{ mV} + 6 \text{ mV}} = \frac{8 \text{ mV}}{20 \text{ mV}} = 0.4$

So, the modulation index is 0.4, which means the degree of modulation is 0.4.