QJEEM23Phd1d0: JEE Main 2023 Physics - Class 12 JEEM23Phd1d0 Solution: As shown in the figure, the voltmeter reads 2   V across 5 …

Step-by-Step Verified Solution

$$i_1=\frac{2V}{5\mathrm{\Omega }}=\frac{2}{5}\mathrm{A}$$


$$i=\frac{1V}{2\mathrm{\Omega }}=\frac{1}{2}A$$

$\therefore$ Current through voltmeter $=i-i_1$

$$=\frac{1}{2}-\frac{2}{5}=\frac{5-4}{10}=\frac{1}{10}\mathrm{A}$$

$\therefore$ For voltmeter

$$2=\left(\frac{1}{10}\right)R\Rightarrow R=20\mathrm{\Omega }$$