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QJEEM23Phd162: JEE Main 2023 Physics - Class 12 JEEM23Phd162 Solution: Unpolarised light is incident on the boundary between two…

Unpolarised light is incident on the boundary between two dielectric media, whose dielectric constants are 2.8 (medium −1-1 ) and 6.8 (medium −2-2 ), respectively. To satisfy the condition, so that the reflected and refracted rays are perpendicular to each other, the angle of incidence should be tan⁡−1(1+10θ)12{\tan ^{ - 1}}{\left( {1 + {{10} \over \theta }} \right)^{{1 \over 2}}} the value of θ\theta is __________.

(Given for dielectric media, μr=1\mu_r=1 )

Step-by-Step Verified Solution

We know that

tan⁡θ0=μ2μ1\tan {\theta _0} = {{{\mu _2}} \over {{\mu _1}}}

tan⁡θ0=6.82.8=177\tan {\theta _0} = \sqrt {{{6.8} \over {2.8}}} = \sqrt {{{17} \over 7}}

θ0=tan⁡−11+107⇒θ=7{\theta _0} = {\tan ^{ - 1}}\sqrt {1 + {{10} \over 7}} \Rightarrow \theta = 7

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