Verified Solution • 2025–26 Session moderate

QJEEM23Phcd79: JEE Main 2023 Physics - Class 12 JEEM23Phcd79 Solution: The electric field and magnetic field components of an…

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by

Ex=Eosin⁡(kz−ωt)

By=Bosin⁡(kz−ωt)

Then the correct relation between E0 and B0 is given by

Multiple Choice Options

  • A EoBo=ωk
  • B E0=kB0
  • C kE0=ωB0
  • D ωE0=kB0

Step-by-Step Verified Solution

Ex=E0sin⁡(kz−ωt)E_{x}=E_{0} \sin (k z-\omega t)

By=B0sin⁡(kz−ωt)B_{y}=B_{0} \sin (k z-\omega t)

∵\because Velocity =E0B0=\frac{E_{0}}{B_{0}}

ωk=E0B0\frac{\omega}{k}=\frac{E_{0}}{B_{0}}

ωB0=kE0\omega B_{0}=k E_{0}

Related Learning Resources & Exam Preparation