QJEEM23Phc582: JEE Main 2023 Physics - Class 11 JEEM23Phc582 Solution: If the maximum load carried by an elevator is ( - Passengers +…

First, let's find the total weight of the elevator and passengers:

Total weight = (mass of passengers + mass of elevator) × g

Total weight = (600 kg + 800 kg) × 10 m/s²

Total weight = 1400 kg × 10 m/s² = 14,000 N

Now, we need to calculate the total force acting on the elevator as it moves upwards. Since the elevator is moving at a constant speed, the net force acting on it is zero. Therefore, the tension in the cable must balance the total weight and frictional force:

Tension = Total weight + Frictional force Tension = 14,000 N + 2,000 N = 16,000 N

The power used by the motor can be calculated using the formula:

Power = Force × Velocity

Here, the force is the tension in the cable, and the velocity is the speed of the elevator:

Power = 16,000 N × 3 m/s = 48,000 W

To convert the power to kilowatts, divide by 1,000:

Power = 48,000 W / 1,000 = 48 kW

So, the maximum power used by the motor is 48 kW.