QJEEM23Phc2ea: JEE Main 2023 Physics - Class 11 JEEM23Phc2ea Solution: A stone tied to long string at its end is making 28 revolutions …

Question

Verified Solution • 2025–26 Session moderate

A stone tied to

180 \mathrm{~cm}

long string at its end is making 28 revolutions in horizontal circle in every minute. The magnitude of acceleration of stone is

\frac{1936}{x} ms^{-2}

. The value of

x

________. (Take

\pi=\frac{22}{7}

)

Accepted Answer

Acceleration of stone

a=\frac{v^{2}}{r}=\omega^{2} R

\begin{aligned}&amp; a=\left(\frac{28 \times 2}{60} \times \frac{22}{7}\right)^{2} \times 1.8 \\\\&amp; =\frac{1936}{125}\end{aligned}

So,

x=125

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