QJEEM23Phc266: JEE Main 2023 Physics - Class 12 JEEM23Phc266 Solution: If two charges q 1 and q 2 are separated with distance 'd' and…

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QJEEM23Phc266: JEE Main 2023 Physics - Class 12 JEEM23Phc266 Solution: If two charges q 1 and q 2 are separated with distance 'd' and…

If two charges q $_{1}$ and q $_{2}$ are separated with distance 'd' and placed in a medium of dielectric constant K. What will be the equivalent distance between charges in air for the same electrostatic force?

Multiple Choice Options

A dk
B 1.5dk
C kd
D 2dk

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Accepted Answer

JEE Main 2023 (Online) 24th January Morning Shift Physics - Electrostatics Question 67 English Explanation

\begin{aligned} dielectric constant = K \\ F_{medium} = \frac{1}{4 π (K ε_{0})} \times \frac{q_{1} q_{2}}{d^{2}} \\ ∵ F_{air} = F_{medium} \\ \frac{1}{4 π ε_{0}} \frac{q_{1} q_{2}}{{(d_{air})}^{2}} = \frac{1}{4 π (K ε_{0})} \frac{q_{1} q_{2}}{d^{2}} \\ ∴ d_{air} = d \sqrt{K} \end{aligned}

QJEEM23Phc266: JEE Main 2023 Physics - Class 12 JEEM23Phc266 Solution: If two charges q 1 and q 2 are separated with distance 'd' and…

Multiple Choice Options

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