Verified Solution • 2025–26 Session moderate

QJEEM23Phad8d: JEE Main 2023 Physics - Class 12 JEEM23Phad8d Solution: A square shaped coil of area having 600 turns rotates in a…

A square shaped coil of area 70 cm270 \mathrm{~cm}^{2} having 600 turns rotates in a magnetic field of 0.4 wbm−20.4 ~\mathrm{wbm}^{-2} , about an axis which is parallel to one of the side of the coil and perpendicular to the direction of field. If the coil completes 500 revolution in a minute, the instantaneous emf when the plane of the coil is inclined at 60∘60^{\circ} with the field, will be ____________ V. (Take π=227\pi=\frac{22}{7} )

Step-by-Step Verified Solution

Area (A)=70 cm2=70×10−4 m2(\mathrm{A})=70 \mathrm{~cm}^2=70 \times 10^{-4} \mathrm{~m}^2

B=0.4 T\mathrm{B}=0.4 \mathrm{~T}

f=500 revolution 60 minute =50060 rev. sec.f=\frac{500 \text { revolution }}{60 \text { minute }}=\frac{500}{60} \frac{\text { rev. }}{\mathrm{sec} .}

Induced emf in rotating coil is given by

amp;e=NωBAsin⁡θamp;=600×2×227×50060×0.4×70×10−4sin⁡30∘amp;=600×2×227×5006×0.4×70×10−4×12amp;=44 Volt \begin{aligned}& e=N \omega B A \sin \theta \\\\& =600 \times 2 \times \frac{22}{7} \times \frac{500}{60} \times 0.4 \times 70 \times 10^{-4} \sin 30^{\circ} \\\\& =600 \times 2 \times \frac{22}{7} \times \frac{500}{6} \times 0.4 \times 70 \times 10^{-4} \times \frac{1}{2} \\\\& =44 \text { Volt }\end{aligned}

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring