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QJEEM23Phad5d: JEE Main 2023 Physics - Class 11 JEEM23Phad5d Solution: The figure shows a liquid of given density flowing steadily in…

JEE Main 2023 (Online) 13th April Morning Shift Physics - Properties of Matter Question 77 English

The figure shows a liquid of given density flowing steadily in horizontal tube of varying cross - section. Cross sectional areas at A is 1.5 cm2, and B is 25 mm2, if the speed of liquid at B is 60 cm/s then (PA−PB) is :

(Given PA and PB are liquid pressures at A and B% points.

density ρ=1000 kg m−3

A and B are on the axis of tube

Multiple Choice Options

  • A 27 Pa
  • B 175 Pa
  • C 135 Pa
  • D 36 Pa

Step-by-Step Verified Solution

From continuity theorem A1 V1=A2 V2\mathrm{A}_1 \mathrm{~V}_1=\mathrm{A}_2 \mathrm{~V}_2

1.5×V1=25×10−2×60 V1=25×60×10−2×101.5 V1=10 cm/s

By Bernoulli's theorem

P1+12×1000×(0.1)2=P2+12×1000×(0.6)2P1+5=P2+12×1000×36×10−2P1+5=P2+180P1−P2=175 Pa

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