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QJEEM23Phaa0e: JEE Main 2023 Physics - Class 12 JEEM23Phaa0e Solution: Ratio of thermal energy released in two resistors R and 3R…

Ratio of thermal energy released in two resistors R and 3R connected in parallel in an electric circuit is :

Multiple Choice Options

  • A 1:01
  • B 1:27
  • C 1:03
  • D 3:01

Step-by-Step Verified Solution

For parallel connection, potential difference is same (v)(v)

amp;P1=(v2R1)amp;P2=(v2R2)amp;P1P2=H1H2=(R2R1)=3RR=(3:1)\begin{aligned}& P_{1}=\left(\frac{v^{2}}{R_{1}}\right) \\\\& P_{2}=\left(\frac{v^{2}}{R_{2}}\right) \\\\& \frac{P_{1}}{P_{2}}=\frac{H_{1}}{H_{2}}=\left(\frac{R_{2}}{R_{1}}\right)=\frac{3 R}{R}=(3: 1)\end{aligned}

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