QJEEM23Pha9e3: JEE Main 2023 Physics - Class 11 JEEM23Pha9e3 Solution: A particle starts with an initial velocity of 10.0   ms −…

To find the time taken by the particle to reach the velocity of $$60.0{\mathrm{ms}}^{-1}$$, we can use the formula:

$$v=u+at$$

Where: $$v$$ is the final velocity, $$u$$ is the initial velocity, $$a$$ is the acceleration, and $$t$$ is the time taken.

Plugging in the given values:

$$60.0{\mathrm{ms}}^{-1}=10.0{\mathrm{ms}}^{-1}+2.0{\mathrm{ms}}^{-2}\cdot t$$

Solve for $$t$$:

$$50.0{\mathrm{ms}}^{-1}=2.0{\mathrm{ms}}^{-2}\cdot t$$

$$t=\frac{50.0{\mathrm{ms}}^{-1}}{2.0{\mathrm{ms}}^{-2}}=25\mathrm{s}$$

So, the time taken by the particle to reach the velocity of $$60.0{\mathrm{ms}}^{-1}$$ is 25 seconds.