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QJEEM23Ph9c73: JEE Main 2023 Physics - Class 12 JEEM23Ph9c73 Solution: A electron beam is used to bombard gaseous hydrogen at room…

A 12.5 eV12.5 \mathrm{~eV} electron beam is used to bombard gaseous hydrogen at room temperature. The number of spectral lines emitted will be:

Multiple Choice Options

  • A 2
  • B 4
  • C 3
  • D 1

Step-by-Step Verified Solution

The energy of an electron in an excited state of hydrogen is given by the equation:

Code snippet

E=−13.61n2 eVE = -13.6 \frac{1}{n^2} \mathrm{~eV}

where n is the principal quantum number of the state.

The energy of the electron beam is 12.5 eV, which is enough to excite the electron to the n = 3 state.

The possible transitions from n = 3 to lower energy states are:

n = 3 to n = 2, with a wavelength of 656.33 nm (H-alpha)

n = 3 to n = 1, with a wavelength of 102.57 nm (Lyman-alpha)

n = 2 to n = 1, with a wavelength of 121.57 nm (Lyman-beta)

Therefore, there are 3 possible spectral lines that can be emitted.

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