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QJEEM23Ph8da6: JEE Main 2023 Physics - Class 12 JEEM23Ph8da6 Solution: As shown in the figure, two parallel plate capacitors having…

As shown in the figure, two parallel plate capacitors having equal plate area of 200 cm2200 \mathrm{~cm}^{2} are joined in such a way that a≠ba \neq b . The equivalent capacitance of the combination is x∈0 Fx \in_{0} \mathrm{~F} . The value of xx is ____________.

JEE Main 2023 (Online) 6th April Evening Shift Physics - Capacitor Question 25 English

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amp;c=ε0A(d−c)amp;=ε0×200×10−44×10−3amp;∴x=5\begin{aligned}& c=\frac{\varepsilon_0 A}{(d-c)} \\\\& =\frac{\varepsilon_0 \times 200 \times 10^{-4}}{4 \times 10^{-3}} \\\\& \therefore x=5\end{aligned}

The situation is equivalent to a conducting slab placed between the plates

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