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QJEEM23Ph896b: JEE Main 2023 Physics - Class 12 JEEM23Ph896b Solution: A message signal of frequency 5 kHz is used to modulate a…

A message signal of frequency 5 kHz is used to modulate a carrier signal of frequency 2 MHz. The bandwidth for amplitude modulation is :

Multiple Choice Options

  • A 10 kHz
  • B 2.5 kHz
  • C 20 kHz
  • D 5 kHz

Step-by-Step Verified Solution

Given

Signal frequency fm = 5kHz

Carrier wave frequency fc=2MHzf_c=2 \mathrm{MHz} fc=2000KHz\mathrm{f}_{\mathrm{c}}=2000 \mathrm{KHz}

The resultant signal will have band width of frequency given by

amp;[(fc+fm)−(fc−fm)]amp;⇒[(2000+5)−(2000−5)]kHzamp;⇒10kHz\begin{aligned}& {\left[\left(f_c+f_m\right)-\left(f_c-f_m\right)\right]} \\\\& \Rightarrow[(2000+5)-(2000-5)] \mathrm{kHz} \\\\& \Rightarrow 10 \mathrm{kHz}\end{aligned}

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