QJEEM23Ph8623: JEE Main 2023 Physics - Class 11 JEEM23Ph8623 Solution: From the v − t graph shown, the ratio of distance to…

Question

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From the $v - t$ graph shown, the ratio of distance to displacement in $25 s$ of motion is:

JEE Main 2023 (Online) 11th April Morning Shift Physics - Motion in a Straight Line Question 24 English

Accepted Answer

Area under the graph from

t=0

to

t=20 \mathrm{sec}=200 \mathrm{~m}

Area under the graph from

\mathrm{t}=20

to

t=25 \mathrm{sec}=50 \mathrm{~m}

So distance covered

=(200+50) \mathrm{m}=250 \mathrm{~m}

Displacement

=(200-50) \mathrm{m}=150 \mathrm{~m}

∴

\frac{distance}{displacement} = \frac{250}{150} = (\frac{5}{3})

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