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QJEEM23Ph8416: JEE Main 2023 Physics - Class 12 JEEM23Ph8416 Solution: When two resistance and connected in series and introduced into …

When two resistance R1\mathrm{R_1} and R2\mathrm{R_2} connected in series and introduced into the left gap of a meter bridge and a resistance of 10 Ω\Omega is introduced into the right gap, a null point is found at 60 cm from left side. When R1\mathrm{R_1} and R2\mathrm{R_2} are connected in parallel and introduced into the left gap, a resistance of 3 Ω\Omega is introduced into the right gap to get null point at 40 cm from left end. The product of R1\mathrm{R_1} R2\mathrm{R_2} is ____________ Ω2\Omega^2

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As per given information

R1+R210=0.60.4{{{R_1} + {R_2}} \over {10}} = {{0.6} \over {0.4}} ...... (1)

& R1R2R1+R23=0.40.6{{{{{R_1}{R_2}} \over {{R_1} + {R_2}}}} \over 3} = {{0.4} \over {0.6}} ..... (2)

⇒R1+R2=15&R1R2=30]⇒R1R2=30Ω2

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