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QJEEM23Ph8254: JEE Main 2023 Physics - Class 11 JEEM23Ph8254 Solution: The displacement equations of two interfering waves are given…

The displacement equations of two interfering waves are given by

y1=10sin⁡(ωt+π3)cm,y2=5[sin⁡ωt+3cos⁡ωt]cmy_{1}=10 \sin \left(\omega t+\frac{\pi}{3}\right) \mathrm{cm}, y_{2}=5[\sin \omega t+\sqrt{3} \cos \omega t] \mathrm{cm} respectively.

The amplitude of the resultant wave is _______ cm\mathrm{cm} .

Step-by-Step Verified Solution

Given, y1=10sin⁡(ωt+π3)cmy_{1}=10 \sin \left(\omega t+\frac{\pi}{3}\right) \mathrm{cm} and

y2=5(sin⁡ωt+3cos⁡ωt)y_{2}=5(\sin \omega t+\sqrt{3} \cos \omega t)

=10sin⁡(ωt+π3)=10 \sin \left(\omega t+\frac{\pi}{3}\right)

Thus the phase difference between the waves is 0 .

 so A=A1+A2=20 cm\text { so } A=A_{1}+A_{2}=20 \mathrm{~cm}

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