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QJEEM23Ph7912: JEE Main 2023 Physics - Class 11 JEEM23Ph7912 Solution: A body is moving with constant speed, in a circle of radius .…

A body is moving with constant speed, in a circle of radius 10 m10 \mathrm{~m} . The body completes one revolution in 4 s4 \mathrm{~s} . At the end of 3rd second, the displacement of body (in m\mathrm{m} ) from its starting point is :

Multiple Choice Options

  • A 15π15 \pi
  • B 30
  • C 10210 \sqrt{2}
  • D 5π5 \pi

Step-by-Step Verified Solution

amp;ω=2πT=2π4=π2rad/samp;θ=ωtamp;θ=π2×3amp;θ=3π2rad\begin{aligned}& \mathrm{\omega}=\frac{2 \pi}{\mathrm{T}}=\frac{2 \pi}{4}=\frac{\pi}{2} \mathrm{rad} / \mathrm{s} \\\\& \theta=\mathrm{\omega t} \\\\& \theta=\frac{\pi}{2} \times 3 \\\\& \theta=\frac{3 \pi}{2} \mathrm{rad}\end{aligned}

JEE Main 2023 (Online) 31st January Evening Shift Physics - Circular Motion Question 30 English Explanation

amp;r=10 mamp;T=4secamp;d=2(10)m\begin{aligned}& r=10 \mathrm{~m} \\\\& T=4 \mathrm{sec} \\\\& d=\sqrt{2}(10) \mathrm{m}\end{aligned}

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