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QJEEM23Ph7807: JEE Main 2023 Physics - Class 12 JEEM23Ph7807 Solution: A car travels a distance of ' ' with speed and then same…

A car travels a distance of ' xx ' with speed v1v_1 and then same distance ' xx ' with speed v2v_2 in the same direction. The average speed of the car is :

Multiple Choice Options

  • A v1v22(v1+v2){{{v_1}{v_2}} \over {2({v_1} + {v_2})}}
  • B 2v1v2v1+v2{{2{v_1}{v_2}} \over {{v_1} + {v_2}}}
  • C 2xv1+v2{{2x} \over {{v_1} + {v_2}}}
  • D v1+v22{{{v_1} + {v_2}} \over 2}

Step-by-Step Verified Solution

amp; Average velocity = Total displacement  Total time amp;=x+xxv1+xv2=2v1v2v1+v2\begin{aligned}& \text { Average velocity }=\frac{\text { Total displacement }}{\text { Total time }} \\\\& =\frac{\mathrm{x}+\mathrm{x}}{\frac{\mathrm{x}}{\mathrm{v}_1}+\frac{\mathrm{x}}{\mathrm{v}_2}}=\frac{2 \mathrm{v}_1 \mathrm{v}_2}{\mathrm{v}_1+\mathrm{v}_2}\end{aligned}

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