Verified Solution • 2025–26 Session moderate

QJEEM23Ph74d6: JEE Main 2023 Physics - Class 11 JEEM23Ph74d6 Solution: Given below are two statements : Statement I : The temperature…

Given below are two statements :

Statement I : The temperature of a gas is −73∘-73^\circ C. When the gas is heated to 527∘527^\circ C, the root mean square speed of the molecules is doubled.

Statement II : The product of pressure and volume of an ideal gas will be equal to translational kinetic energy of the molecules.

In the light of the above statements, choose the correct answer from the option given below :

Multiple Choice Options

  • A Statement I is true but Statement II is false
  • B Both Statement I and Statement II are true
  • C Statement I is false but Statement II is true
  • D Both Statement I and Statement II are false

Step-by-Step Verified Solution

Ti=200 Kvrms∝TT_{i}=200 \mathrm{~K} \quad\quad v_{\mathrm{rms}} \propto \sqrt{T}

Tf=800 KT_{f}=800 \mathrm{~K}

ViVf=TiTf=200800=14=12\frac{V_{i}}{V_{f}}=\sqrt{\frac{T_{i}}{T_{f}}}=\sqrt{\frac{200}{800}}=\sqrt{\frac{1}{4}}=\frac{1}{2}

Vf=2ViV_{f}=2 V_{i}

Translational K.E. =(32PV)=\left(\frac{3}{2} P V\right)

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring