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QJEEM23Ph71dd: JEE Main 2023 Physics - Class 12 JEEM23Ph71dd Solution: In the given circuit, rms value of current through the resistor …

In the given circuit, rms value of current (Irms)\left(I_{\mathrm{rms}}\right) through the resistor RR is:

JEE Main 2023 (Online) 30th January Evening Shift Physics - Alternating Current Question 48 English

Multiple Choice Options

  • A 22 A2 \sqrt{2} \mathrm{~A}
  • B 2 A2 \mathrm{~A}
  • C 12 A\frac{1}{2} \mathrm{~A}
  • D 20 A20 \mathrm{~A}

Step-by-Step Verified Solution

Irms=Vrmsz=20021002+(200−100)2{I_{rms}} = {{{V_{rms}}} \over z} = {{200\sqrt 2 } \over {\sqrt {{{100}^2} + {{(200 - 100)}^2}} }}

=20021002= {{200\sqrt 2 } \over {100\sqrt 2 }}

= 2 A

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