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QJEEM23Ph70dc: JEE Main 2023 Physics - Class 12 JEEM23Ph70dc Solution: A 1 m long metal rod XY completes the circuit as shown in…

A 1 m long metal rod XY completes the circuit as shown in figure. The plane of the circuit is perpendicular to the magnetic field of flux density 0.15 T. If the resistance of the circuit is 5Ω, the force needed to move the rod in direction, as indicated, with a constant speed of 4 m/s will be ____________ 10−3 N.

JEE Main 2023 (Online) 10th April Morning Shift Physics - Electromagnetic Induction Question 29 English

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JEE Main 2023 (Online) 10th April Morning Shift Physics - Electromagnetic Induction Question 29 English Explanation

To move the rod with a constant velocity v=4 m s−1v=4 \mathrm{~m} \mathrm{~s}^{-1}

Fnet \mathrm{F}_{\text {net }} on the rod should be zero.

F=Bil=0.15(BlvR)l=0.15(0.15×1×45)×1=0.03×0.15×4=180×10−4 N=18×10−3 N

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