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QJEEM23Ph7058: JEE Main 2023 Physics - Class 12 JEEM23Ph7058 Solution: If a source of electromagnetic radiation having power 15   …

If a source of electromagnetic radiation having power 15 kW produces 1016 photons per second, the radiation belongs to a part of spectrum is.

(Take Planck constant h=6×10−34Js )

Multiple Choice Options

  • A Gamma rays
  • B Radio waves
  • C Micro waves
  • D Ultraviolet rays

Step-by-Step Verified Solution

 Energy of one photon = Power  Photon frequency E=hv=15×1031016⇒v=15×10−136×10−34=2.5×1021

So gamma Rays.

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