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QJEEM23Ph6fda: JEE Main 2023 Physics - Class 12 JEEM23Ph6fda Solution: Two long straight wires P and Q carrying equal current 10A each …

Two long straight wires P and Q carrying equal current 10A each were kept parallel to each other at 5 cm distance. Magnitude of magnetic force experienced by 10 cm length of wire P is F1. If distance between wires is halved and currents on them are doubled, force F2 on 10 cm length of wire P will be:

Multiple Choice Options

  • A F18
  • B 10 F1
  • C F110
  • D 8 F1

Step-by-Step Verified Solution

 Force per unit length between two parallel straight wires =μ0i1i22πdF1 F2=μ0(10)22π(5 cm)μ0(20)22π(5 cm2)=18⇒F2=8 F1

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