QJEEM23Ph6b1b: JEE Main 2023 Physics - Class 12 JEEM23Ph6b1b Solution: In the given circuit, the equivalent resistance between the…

Both $4 \Omega$ resistance and left $2 \Omega$ resistance get short-circuited. So, no current will flow through them.

Remove the resistors that have no current. Now the equivalent circuit becomes -


$\begin{aligned}& \mathrm{R}_{\mathrm{eq}}=3+(2 \| 2)+6 \\\\& \mathrm{R}_{\mathrm{eq}}=3+1+6 \\\\& \mathrm{R}_{\mathrm{eq}}=10 \Omega\end{aligned}$