Verified Solution • 2025–26 Session moderate

QJEEM23Ph6a6c: JEE Main 2023 Physics - Class 11 JEEM23Ph6a6c Solution: A machine gun of mass fires bullets at the rate of 180 bullets…

A machine gun of mass 10 kg10 \mathrm{~kg} fires 20 g20 \mathrm{~g} bullets at the rate of 180 bullets per minute with a speed of 100 m s−1100 \mathrm{~m} \mathrm{~s}^{-1} each. The recoil velocity of the gun is

Multiple Choice Options

  • A 0.02 m/s0.02 \mathrm{~m} / \mathrm{s}
  • B 1.5 m/s1.5 \mathrm{~m} / \mathrm{s}
  • C 2.5 m/s2.5 \mathrm{~m} / \mathrm{s}
  • D 0.6 m/s0.6 \mathrm{~m} / \mathrm{s}

Step-by-Step Verified Solution

Momentum of bullets per unit time

=180×201000×10060= {{180 \times {{20} \over {1000}} \times 100} \over {60}} kg m/s 2^2

= 6 N

⇒\Rightarrow Force on gun = 6 N

We cannot calculate recoil velocity with the given data.

If we consider recoil velocity at t=1t = 1 s, then

Vrecoil=u+at{V_{\mathrm{recoil}}} = u + at

=0+610×1= 0 + {6 \over {10}} \times 1 = 0.6 m/s

Related Learning Resources & Exam Preparation