Verified Solution • 2025–26 Session moderate

QJEEM23Ph6711: JEE Main 2023 Physics - Class 11 JEEM23Ph6711 Solution: Match List I with List II .tg…

Match List I with List II

LIST I LIST II
A. Angular momentum I. [ML2 T−2]\left[\mathrm{ML}^{2} \mathrm{~T}^{-2}\right]
B. Torque II. [ML−2 T−2]\left[\mathrm{ML}^{-2} \mathrm{~T}^{-2}\right]
C. Stress III [ML2 T−1]\left[\mathrm{ML}^{2} \mathrm{~T}^{-1}\right]
D. Pressure gradient IV. [ML−1 T−2]\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right]

Choose the correct answer from the options given below:

Multiple Choice Options

  • A A - I, B - IV, C - III, D - II
  • B A - III, B - I, C - IV, D - II
  • C A - IV, B - II, C - I, D - III
  • D A - II, B - III, C - IV, D - I

Step-by-Step Verified Solution

L⃗=r⃗×p⃗⇒[L]=[M0 L1 T0][M1 L1 T−1]\vec{L}=\vec{r} \times \vec{p} \Rightarrow[\mathrm{L}]=\left[\mathrm{M}^{0} \mathrm{~L}^{1} \mathrm{~T}^{0}\right]\left[\mathrm{M}^{1} \mathrm{~L}^{1} \mathrm{~T}^{-1}\right]

=[M1 L2 T−1]

τ→=r→×F→⇒[τ]=[L1][MLT−2]=[ML2 T−2]

Stress ≡\equiv Pressure =FA⇒[=\frac{F}{A} \Rightarrow[ Stress ]=[ML−1 T−2]]=\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right]

Pressure Gradient =dPdx⇒[=\frac{d P}{d x} \Rightarrow[ Pressure Gradient ]] =[ML−2 T−2]

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