Verified Solution • 2025–26 Session moderate

QJEEM23Ph64dd: JEE Main 2023 Physics - Class 12 JEEM23Ph64dd Solution: A series circuit consists of , and . The input voltage is 2500…

A series LCR\mathrm{LCR} circuit consists of R=80Ω,XL=100Ω\mathrm{R}=80 \Omega, \mathrm{X}_{\mathrm{L}}=100 \Omega , and XC=40Ω\mathrm{X}_{\mathrm{C}}=40 \Omega . The input

voltage is 2500 cos⁡(100πt)V\cos (100 \pi \mathrm{t}) \mathrm{V} . The amplitude of current, in the circuit, is _________ A.

Step-by-Step Verified Solution

ω=100π\omega=100 \pi

amp; So Z=R2+(XL−XC)2amp;=802+(100−40)2amp;=100Ωamp;i0=V0Z=2500100 A=25 A\begin{aligned}& \text { So } Z=\sqrt{R^{2}+\left(X_{L}-X_{C}\right)^{2}} \\\\& =\sqrt{80^{2}+(100-40)^{2}} \\\\& =100 \Omega \\\\& i_{0}=\frac{V_{0}}{Z}=\frac{2500}{100} \mathrm{~A}=25 \mathrm{~A}\end{aligned}

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