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QJEEM23Ph5fa6: JEE Main 2023 Physics - Class 11 JEEM23Ph5fa6 Solution: Under the same load, wire A having length and cross section…

Under the same load, wire A having length 5.0 m5.0 \mathrm{~m} and cross section 2.5×10−5 m22.5 \times 10^{-5} \mathrm{~m}^{2} stretches uniformly by the same amount as another wire B of length 6.0 m6.0 \mathrm{~m} and a cross section of 3.0×10−53.0 \times 10^{-5} m2\mathrm{m}^{2} stretches. The ratio of the Young's modulus of wire A to that of wire BB will be :

Multiple Choice Options

  • A 1:21: 2
  • B 1:41: 4
  • C 1:11: 1
  • D 1:101: 10

Step-by-Step Verified Solution

Δℓ=FℓSY\Delta \ell=\frac{F \ell}{S Y}

FF is same for both wire and Δℓ\Delta \ell is also same

amp;ΔℓF=ℓSYamp;⇒ℓASAYA=ℓBSBYBamp;⇒52.5×YA=63×YBamp;⇒YAYB=1\begin{aligned}& \frac{\Delta \ell}{F}=\frac{\ell}{S Y} \\\\& \Rightarrow \frac{\ell_{A}}{S_{A} Y_{A}}=\frac{\ell_{B}}{S_{B} Y_{B}} \\\\& \Rightarrow \frac{5}{2.5 \times Y_{A}}=\frac{6}{3 \times Y_{B}} \\\\& \Rightarrow \frac{Y_{A}}{Y_{B}}=1\end{aligned}

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