Verified Solution • 2025–26 Session moderate

QJEEM23Ph5ce6: JEE Main 2023 Physics - Class 12 JEEM23Ph5ce6 Solution: Two polaroide and are placed in such a way that the pass-axis…

Two polaroide A\mathrm{A} and B\mathrm{B} are placed in such a way that the pass-axis of polaroids are perpendicular to each other. Now, another polaroid C\mathrm{C} is placed between A\mathrm{A} and B\mathrm{B} bisecting angle between them. If intensity of unpolarized light is I0\mathrm{I}_{0} then intensity of transmitted light after passing through polaroid B\mathrm{B} will be:

Multiple Choice Options

  • A I04\frac{I_{0}}{4}
  • B I08\frac{I_{0}}{8}
  • C Zero
  • D I02\frac{I_{0}}{2}

Step-by-Step Verified Solution

IA=Io2\mathrm{I}_{\mathrm{A}}=\frac{\mathrm{I}_{\mathrm{o}}}{2}

IC=Io2cos⁡245=Io4\mathrm{I_C}=\frac{\mathrm{I}_{\mathrm{o}}}{2} \cos ^{2} 45=\frac{\mathrm{I}_{\mathrm{o}}}{4}

IB=ICcos⁡245=Io8\mathrm{I}_{\mathrm{B}}=\mathrm{I}_{\mathrm{C}} \cos ^{2} 45=\frac{\mathrm{I}_{\mathrm{o}}}{8}

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