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QJEEM23Ph56c0: JEE Main 2023 Physics - Class 11 JEEM23Ph56c0 Solution: Match List I with List II .tg…

Match List I with List II

List-I
 List-II
A. Planck's constant (h) I. [M1 L2 T−2]\mathrm{[{M^1}\,{L^2}\,{T^{ - 2}}]}
B. Stopping potential (Vs) II. [M1 L1 T−1]\mathrm{[{M^1}\,{L^1}\,{T^{ - 1}}]}
C. Work function ( ϕ\phi ) III. [M1 L2 T−1]\mathrm{[{M^1}\,{L^2}\,{T^{ - 1}}]}
D. Momentum (p) IV. [M1 L2 T−3 A−1]\mathrm{[{M^1}\,{L^2}\,{T^{ - 3}}\,{A^{ - 1}}]}

Choose the correct answer from the options given below :

Multiple Choice Options

  • A A-I, B-III, C-IV, D-II
  • B A-III, B-IV, C-I, D-II
  • C A-II, B-IV, C-III, D-I
  • D A-III, B-I, C-II, D-IV

Step-by-Step Verified Solution

(A) Planck's constant

amp;hv=Eamp;h=Ev=M1 L2 T−2 T−1=M1 L2 T−1...(III)\begin{aligned}& \mathrm{h} v=\mathrm{E} \\\\& \mathrm{h}=\frac{\mathrm{E}}{v}=\frac{\mathrm{M}^1 \mathrm{~L}^2 \mathrm{~T}^{-2}}{\mathrm{~T}^{-1}}=\mathrm{M}^1 \mathrm{~L}^2 \mathrm{~T}^{-1} \quad...(\text{III})\end{aligned}

(B) E=qV\mathrm{E}=\mathrm{qV}

V=Eq=M1L2T−2A1T1=M1L2T−3A−1 (IV) V=\frac{E}{q}=\frac{M^1 L^2 T^{-2}}{A^1 T^1}=M^1 L^2 T^{-3} A^{-1} \text { (IV) }

(C) ϕ(\phi( work function )=)= energy

=M1 L2 T−2....(I)=\mathrm{M}^1 \mathrm{~L}^2 \mathrm{~T}^{-2} \quad....(\text{I})

(D) Momentum (p) = F.t

amp;=M1 L1 T−2 T1amp;=M1 L1 T−1....(II)\begin{aligned}& =\mathrm{M}^1 \mathrm{~L}^1 \mathrm{~T}^{-2} \mathrm{~T}^1 \\\\& =\mathrm{M}^1 \mathrm{~L}^1 \mathrm{~T}^{-1} \quad....(\text{II})\end{aligned}

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