Verified Solution • 2025–26 Session moderate

QJEEM23Ph5621: JEE Main 2023 Physics - Class 12 JEEM23Ph5621 Solution: When a resistance of is shunted with a moving coil…

When a resistance of $5 ~\Omega$ is shunted with a moving coil galvanometer, it shows a full scale deflection for a current of $250 \mathrm{~mA}$ , however when $1050 ~\Omega$ resistance is connected with it in series, it gives full scale deflection for 25 volt. The resistance of galvanometer is ____________ $\Omega$ .

Step-by-Step Verified Solution

Given:

\frac{250 \ \text{mA} \times 5}{5 + R_G} = i

i = \frac{25}{1050 + R_G}

Equating the two expressions for current,

i

:

\frac{250 \ \text{mA} \times 5}{5 + R_G} = \frac{25}{1050 + R_G}

This equation simplifies to:

100(5 + R_G) = 1050 \times 5 + R_G \times 5

Solving for the resistance of the galvanometer,

R_G

:

95 R_G = 4750

R_G = 50 \ \Omega

So, the resistance of the galvanometer is

50 \ \Omega

.

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