QJEEM23Ph5609: JEE Main 2023 Physics - Class 11 JEEM23Ph5609 Solution: A physical quantity P is given as The percentage error in the…

The percentage error in a quantity that is a product or quotient of other quantities is given by the sum of the percentage errors in those quantities, each multiplied by the power to which it is raised in the expression for the quantity.

Given the physical quantity P as

$P = \frac{a^2b^3}{c\sqrt{d}}$

The percentage error in P, denoted as $\Delta P/P$ , is given by:

$\frac{\Delta P}{P} = 2 \left(\frac{\Delta a}{a}\right) + 3 \left(\frac{\Delta b}{b}\right) + \left(\frac{\Delta c}{c}\right) + \frac{1}{2} \left(\frac{\Delta d}{d}\right)$

Substituting the given percentage errors for a, b, c, and d:

$\frac{\Delta P}{P} = 2(0.01) + 3(0.02) + 0.03 + \frac{1}{2}(0.04) = 0.02 + 0.06 + 0.03 + 0.02 = 0.13$

Therefore, the percentage error in P is 13%.