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QJEEM23Ph4d1a: JEE Main 2023 Physics - Class 11 JEEM23Ph4d1a Solution: Under isothermal condition, the pressure of a gas is given by , …

Under isothermal condition, the pressure of a gas is given by P=a V−3\mathrm{P}=a \mathrm{~V}^{-3} , where aa is a constant and V\mathrm{V} is the volume of the gas. The bulk modulus at constant temperature is equal to

Multiple Choice Options

  • A P2\frac{P}{2}
  • B 2:00 PM
  • C 3:00 PM
  • D P

Step-by-Step Verified Solution

The bulk modulus ( BB ) of a substance is defined as the ratio of the infinitesimal pressure increase ( ΔP\Delta P ) to the relative decrease in volume ( −ΔVV\frac{-\Delta V}{V} ) at constant temperature:

B=−VΔPΔVB = -V \frac{\Delta P}{\Delta V}

To find the bulk modulus for the given pressure-volume relationship, we first need to find the differential change in pressure with respect to volume:

P=aV−3P = aV^{-3}

Differentiate PP with respect to VV :

dPdV=−3aV−4\frac{dP}{dV} = -3aV^{-4}

Now we can use the definition of the bulk modulus:

B=−VΔPΔV=−VdPdVB = -V \frac{\Delta P}{\Delta V} = -V \frac{dP}{dV}

Plug in the value for dPdV\frac{dP}{dV} :

B=−V(−3aV−4)B = -V(-3aV^{-4})

Simplify the expression:

B=3aV−3B = 3aV^{-3}

Notice that 3aV−33aV^{-3} is equal to 3P3P , since P=aV−3P = aV^{-3} :

B=3PB = 3P

Therefore, the bulk modulus at constant temperature is equal to 3P.

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